In `DeltaABC`,ray BD bisects `angleABC` and ray CE bisects `angleACB`.
If seg AB `cong`seg AC, then prove that ED `abs()` BC.

In Delta ABC , ray BD bisects angleABC . A-D-C , side DEabs()side BC , A-E-B , then prove that (AB)/(BC) = (AE)/(EB) .

Ray BD is the angle bisector of angleABC. The perimeter of DeltaABC is

In DeltaABC,angleBAC=120^(@) and AB = AC, then find measure of angleABC .

In the given figure, ray AE || ray BD, ray AF is the bisector of angleEAB and ray BC is the bisector of angleABD . Prove that lineAF || line BC.

In DeltaABC, if M is the midpiont of BC and seg AM bot seg BC, then prove that prove that AB^(2)+AC^(2)=2AM^(2)+2BM^(2).

In the adjoining figure, bisector of angleBAC intersects BC at point D. Prove that AB gt BD .

In DeltaABC , seg AD bot seg BC , DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2) .

In DeltaABC , ray BD bisects /_ABC . A-D-C , side DE|| side BC , A-E-B . Prove that, (AB)/(BC)=(AE)/(EB) . Complete the activity by filling the boxes. In DeltaABC , ray BD is the bisector of /_ABC :.(AB)/(BC)=square ....... (I) (By angle bisector theorem) In DeltaABC , seg DE|| side BC :.(AE)/(EB)=(AD)/(DC) ........ (II) square :.(AB)/(square)=(square)/(EB) .......[From (I) and (II) ]

In triangle ABC , seg AD_|_side BC , B-D-C. Prove that AB^2+CD^2=BD^2+AC^2

Draw a Delta ABC . 1. Bisect angleB and name the point of intersection of AC and the angle bisecto as D. 2. Mesure the sides. AB= square cm , BC = square cm, AD = square cm, DC = square cm 3. Find rations (AB)/(BC) and (AD)/(DC) . 4. You will find that both the rations are almost equal. 5. Bisect remaining angles of the triangle and find the ration as above. Verify that the ratios are equal.