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If in triangle ABC and triangle PQR for ...

If in `triangle ABC and triangle PQR` for some one-one correspondence if `(AB)/(QR)=(BC)/(PR)=(CA)/(PQ)` then: a)`triangle PQR~triangle ABC` b)`triangle PQR~triangle CAB` c)`triangle CBA~triangle PQR` d)`triangle BCA~triangle PQR`

A

`triangle PQR~triangle ABC`

B

`triangle PQR~triangle CAB`

C

`triangle CBA~triangle PQR`

D

`triangle BCA~triangle PQR`

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