यदि `y=x^(2) sin (x^(3))`, हो तो `int y dx` का मान होगा-

Options

A. `-cos (x^(3))+C`
B. `-(cos x^(3)/(3))+C`
C. `cos (x^(3))+C`
D. `(cos x^(3))/(3)+C`

Answer

B

Explanation

`y=x^(2) sin x^(3)`
`int x^(2) sin x^(3) dx" let u "x^(3) rArr du =3x^(2) dx`
`int (sin u du)/3=1/3 (-cos u ) +C=-1/3 cos x^(3)+C`