निम्न का समाकलन करे `int (cos^(3) theta)/(1-sin theta)d theta`

Options

A. `sin theta+(sin^(2) theta)/(2)+C`
B. `sin theta+(cos ^(2) theta)/(2)+C`
C. `cos theta+(cos^(2) theta)/2+C`
D. `sin theta-(cos^(2) theta)/(2)+C`

Answer

A

Explanation

`I ((1-sin^(2) theta))/(1-sin theta) cos d theta" माना "sin theta=t , cos d theta=dt`
`I ((1-t^(2))/(1-t)) dt= int (1+t) dt =t+t^(2)/2+c = sin theta+(sin ^(2) theta)/(2)+C`