यदि `y=x^(2)sinx+(3x)/(tanx)`, हो तो `(dy)/(dx)` होगा :

Options

A. `2xsinx+x^(2)cosx+(3tanx-3xsec^(2)x)/(tan^(2)x)`
B. `2xsinx+x^(2)cosx+(1.5sin(2x)-3x)/(sin^(2)x)`
C. `x^(2)cosx+(3tanx-3xsec^(2)x)//tan^(2)x`
D. `x^(2)cosx-2xsinx-(3tanx-3xsec^(2)x)//tan^(2)x`

Answer

A, B

Explanation

`y=x^(2)sinx+(3x)/(tanx)`
`(dy)/(dx)=x^(2)(d)/(dx)sinx+siny(d)/(dx)(x^(2))+(tan""(d)/(dx)(3t)-3x(d)/(dx)(tanx))/(tan^(2)x)`
`(dy)/(dx)=x^(2)cosy+2xsinx+(3tanx-3xsec^(2)x)/(tan^(2)x)`