A parallel plate capacitor whose capacitance C is 14 pF is charged by a battery to a potential difference V = 12 V between its plates. The charging battery is now disconnected and a porceline plate with k = 7 is inserted between the plates, then the plate would oscillate back and forth between the plates with a constant mechanical energy of `"_____________"` pJ ( Assume no friction )

A parallel plate capacitor having capacitance 12pF is charged bya battery to a potential difference of 10V between its plates. The charging battery is now disonnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is

A parallel plate capacitor whose capacitance C is 13.5 pF is charged by a battery to a potential difference V=12.5V between its plates. The charging battery is now disconnected, and a porcelain slab (k=6.50) is slipped between the plates. (a) What is the potential energy of the capacitor before the slab is inserted? (b) What is the potential energy of the capacitor slab device after the slab is inserted?

In an isolated parallel plate capacitor of capacitance C , the plates have charge Q_(1) and Q_(2) . The potential difference between the plates is

A parallel plate capacitor of capacitance C_(0) is charged with a charge Q_(0) to a potential difference V_(0) and the battery is then disconnected Now a dielectric slab of dielectric constant k is inserted between the plates ofcapacitor. The dimensions of the slab are such that it completely fills the space between the plates, then :

A parallel plate capacitor has plate of area A and separation d .It is charged to a potential difference V_(0) . The charging battery is disconnected and the plates are pulled apart to three times the initial separation.The work required to separate the plates is.

A parallel plate capcitor has plate area A and separation d . It is charged to a potential difference V_(0) . The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is

A pararllel plate capacitor has plates of area A and separation d and is charged to potential diference V . The charging battery is then disconnected and the plates are pulle apart until their separation is 2d . What is the work required to separate the plates?

A capacitor plates are charged by a battery with ‘V’ volts. After charging battery is disconnected and a dielectric slab with dielectric constant ‘K’ is inserted between its plates, the potential across the plates of a capacitor will become

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.