10.0mL of `Na_2CO_3` solution is titrated against 0.2M HCl solution. The following titre values were obtained in 5 readings :
4.8mL, 4.9mL, 5.0mL, 5.0mL, and 5.0mL
Based on these readings, and convention of titrametric estimation the concentration of `Na_2CO_3` solution is.........nM. (Round off to the Nearest Integer).

10ml of Na_2CO_3 war titrated against 0.2M HCl. The following were the titre values obtained (ml) 4.8,4.9,5.0,5.0,5.0. Molarity of Na_2CO_3 ?

Consider titration of NaOH solution versus 1.25M oxalic acid solution. At the end point following burette readings were obtained. (i) 4.5mL (ii) 4.5mL (iii) 4.4mL (iv) 4.4mL (v) 4.4 mL If the volume of oxalic acid taken was 10.0 mL then the molarity of the NaOH solution is ______M. (Rounded-off to the nearest integer)

In 100ml , 0.1N Na_2CO_3.xH_2O solution. Mass of solute is 1.43g, then value of X is:

0.4 g mixture of NaOH, Na_2CO_3 , and some inert N impurities was first titrated with N/(10) HCl using phenolphthalein as an indicator, 17.5 ml. of HCI was required at the end point. After this methyl orange was added and titrated. 1.5 mL of same HCl was required for the next end point. The weight percentage of Na_2CO_3 , in the mixture is (Rounded-off to the nearest integer)

20 mL of 0.5 M HCl is mixed with 30 mL of 0.3 M HCl, the molarity of the resulting solution is :

A student performs a titration with different burettes and find titre values of 25.2 mL, 25.25 mL and 25.0 mL . What is the average titre value based upon rounded off principle ?

200 " mL of " a solution of a mixture of NaOH and Na_2CO_3 was first titrated with 0.1 M HCl using phenolphthalein indicator. 17.5 " mL of " HCl was required for the same HCl was again required for next end point. Find the amount of NaOH and Na_2CO_3 in the mixture.