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Prove that sin^2(18)^@ + cos^2(36)^@ = 3...

Prove that `sin^2(18)^@ + cos^2(36)^@ = 3/4`

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`sin^2 18^@+cos^236^@=`((sqrt5-1)/4)^2+((sqrt5+1)/4)^2=((sqrt5-1)^2+(sqrt5+1))/16 =3/4`
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