Home
Class 11
PHYSICS
To verify Ohm's law, a student is provid...

To verify Ohm's law, a student is provided with a test resistor `R_(T)`, a high resistance `R_(1)` . a small resistance `R_(2)`, two identical galvometers `G_(1)` and `G_(2)` and voltage source `V`. The correct circuit to carry out the experiment is.

Text Solution

AI Generated Solution

The correct Answer is:
To verify Ohm's law using the provided components, we need to set up a circuit that allows us to measure the current through a test resistor and the voltage across it. Here’s a step-by-step solution to create the correct circuit: ### Step-by-Step Solution: 1. **Identify Components**: We have a test resistor \( R_T \), a high resistance \( R_1 \), a small resistance \( R_2 \), and two galvanometers \( G_1 \) and \( G_2 \). 2. **Understanding the Role of Galvanometers**: - \( G_1 \) will be used to measure current, so we need to convert it into an ammeter. - \( G_2 \) will be used to measure voltage, so we need to convert it into a voltmeter. 3. **Creating an Ammeter**: - To convert \( G_1 \) into an ammeter, connect the small resistance \( R_2 \) in parallel with \( G_1 \). This setup allows most of the current to bypass the galvanometer, protecting it from high current while still allowing it to measure the small current flowing through it. 4. **Creating a Voltmeter**: - To convert \( G_2 \) into a voltmeter, connect the high resistance \( R_1 \) in series with \( G_2 \). This configuration ensures that the galvanometer measures the voltage drop across \( R_1 \) while limiting the current through it. 5. **Connecting the Circuit**: - Connect the ammeter setup (i.e., \( G_1 \) and \( R_2 \)) in series with the test resistor \( R_T \). - Connect the voltmeter setup (i.e., \( G_2 \) and \( R_1 \)) across the test resistor \( R_T \). - Finally, connect the entire circuit to the voltage source \( V \). 6. **Final Circuit Layout**: - The circuit should look like this: - The voltage source \( V \) connects to the series combination of \( R_T \) and the ammeter (which is \( G_1 \) and \( R_2 \)). - The voltmeter (which is \( G_2 \) and \( R_1 \)) is connected across \( R_T \).

To verify Ohm's law using the provided components, we need to set up a circuit that allows us to measure the current through a test resistor and the voltage across it. Here’s a step-by-step solution to create the correct circuit: ### Step-by-Step Solution: 1. **Identify Components**: We have a test resistor \( R_T \), a high resistance \( R_1 \), a small resistance \( R_2 \), and two galvanometers \( G_1 \) and \( G_2 \). 2. **Understanding the Role of Galvanometers**: - \( G_1 \) will be used to measure current, so we need to convert it into an ammeter. ...
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTS

    DC PANDEY ENGLISH|Exercise Exercise 3.7|3 Videos
  • EXPERIMENTS

    DC PANDEY ENGLISH|Exercise Exercise 3.8|3 Videos
  • EXPERIMENTS

    DC PANDEY ENGLISH|Exercise Exercise 3.5|2 Videos
  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Integer|17 Videos
  • FLUID MECHANICS

    DC PANDEY ENGLISH|Exercise Medical entranes gallery|49 Videos

Similar Questions

Explore conceptually related problems

You are provided with one low resistance R_(1) and one high resistance R_(H) , and two galvanometers. One galvanometer is to be converted to an ammeter and the other to a voltmeter. Show how you will do this with the help of simple, labelled diagrams.

Two resistors of resistance R_(1) and R_(2) having R_(1) gt R_(2) are connected in parallel. For equivalent resistance R, the correct statement is

Two resistors of resistance R_(1) and R_(2) having R_(1) gt R_(2) are connected in parallel. For equivalent resistance R, the correct statement is

Consider two identical galvanometers and two identical resistors with resistance R . If the internal resistance of the galvanometers R_(c) lt R//2 , which of the following statement(s) about any one of the galvanometers is (are) true?

A cell develops the same power across two resistances R_(1) and R_(2) separately. The internal resistance of the cell is

A cell develops the same power across two resistances R_(1) and R_(2) separately. The internal resistance of the cell is

A resistance R_(1) is connected to a source of constant voltage . On connecting a resistance R_(2) in series with R_(1)

The circuit has resistors of equal resistance R. The equivalent resistance between A and B, when key is closed is R_1 and when key is open is R_2 . Find the ratio R_1 and R_2 .

Statement I : In the circuit in Fig. 7.46 , both cells are ideal and of fixed emf, the resistor R_(1) has fixed resistance and the resistance of resistor R_(2) can be varied ( but R_(2) is always non zero). Then the electric power delivered to the resistor of resistance R_(1) is independent of the value of resistance R_(2) . Statement II: If potential difference across a fixed resistance is unchanged , the poweer delivered to the resistor remains constant.

The circuit shown in the figure above consists of eight resistors, each with resistance R , and a battery with terminal voltage V and negligible internal resistance. The current flowing through the battery is n/4 V/R , then n is