A meter bridge is set- up as shown in figure, to determine an unknown resistance `X` using a standard ` 10 Omega` resistor. The galvanometer shows null point when tapping - key is at `52 cm` mark. The end -corrections are `1 m` and `2 cm` respectively for the ends `A` and `B`. The determined values of `X` is .

(a) `10.2 Omeaga`
(b) `10.6 Omega`
(c) `10.8 Omega`
(d) `11.1 Omega`.

Options

A. (a) 10.2 ohm
B. (b) 10.6 ohm
C. (c) 10.8 ohm
D. (d) 11.1 ohm

Answer

B

Explanation

Using the concept of balanced, Wheatstone bridge, we have,
`P/Q = R/S`
`:. X/((52 +1))=(10)/((48 + 2))`
`:. X=(10 xx 53)/(50) =10.6 Omega`
`:.` Correct option is (b).