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In the previous question, minimum possib...

In the previous question, minimum possible error in area measurement can be.

A

`(a)+- 0.02 cm^2`

B

`(b)+- 0.01 cm^2`.

C

`(c)+- 0.03 cm^2`.

D

(d)zero

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The correct Answer is:
To solve the question regarding the minimum possible error in area measurement, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Area**: The area \( A \) of a rectangle (or any shape) is given by the formula: \[ A = L \times W \] where \( L \) is the length and \( W \) is the width. 2. **Relative Error in Area**: To find the relative error in the area, we can use the formula for relative error: \[ \frac{\Delta A}{A} = \frac{\Delta L}{L} + \frac{\Delta W}{W} \] where \( \Delta A \) is the error in area, \( \Delta L \) is the error in length, and \( \Delta W \) is the error in width. 3. **Consider Minimum Possible Errors**: The minimum possible error in any measurement can theoretically be zero. This means: \[ \Delta L = 0 \quad \text{and} \quad \Delta W = 0 \] 4. **Calculate Minimum Error in Area**: If both the errors in length and width are zero, then substituting these values into the relative error formula gives: \[ \frac{\Delta A}{A} = \frac{0}{L} + \frac{0}{W} = 0 \] This implies that: \[ \Delta A = 0 \times A = 0 \] 5. **Conclusion**: Therefore, the minimum possible error in area measurement can indeed be: \[ \Delta A = 0 \] ### Final Answer: The minimum possible error in area measurement can be \( 0 \). ---
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