Prove that the vectors `A = 2 hati - 3 j+hat k` and `B= hat i+hat j + hat k` are mutually perpendicular.

Explanation

To prove that the vectors \( \mathbf{A} = 2 \hat{i} - 3 \hat{j} + \hat{k} \) and \( \mathbf{B} = \hat{i} + \hat{j} + \hat{k} \) are mutually perpendicular, we need to show that their dot product is equal to zero.

### Step-by-Step Solution:

1. **Write down the vectors**:
\[ \mathbf{A} = 2 \hat{i} - 3 \hat{j} + 1 \hat{k} \]
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