Let a force F be acting on a body free to rotate about a point O and let r the position vector of ant point P on the line of aciton of the force. Then torque `(tau)` of this force abot point O is defined as ` tau = rxxF` Given, `F = (2hati + 3hatj - hatk)N and r = (hati- hatj+6hatk)m` Find the torque of this force.

Explanation

To find the torque \( \tau \) of the force \( F \) about point \( O \), we will use the formula:

\[ \tau = \mathbf{r} \times \mathbf{F} \]

where \( \mathbf{r} \) is the position vector and \( \mathbf{F} \) is the force vector.

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