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Unit vector parallel to the resultant of...

Unit vector parallel to the resultant of vectors `A = 4hatj - 3hatj and B =8hatj+8hatj` will be

A

`(24hati+5hatj)/(13)`

B

`(12hati+5hatj)/(13)`

C

`(6hati+5hatj)/(13)`

D

None of these

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The correct Answer is:
To find the unit vector parallel to the resultant of the vectors \( \mathbf{A} = 4\hat{i} - 3\hat{j} \) and \( \mathbf{B} = 8\hat{i} + 8\hat{j} \), we will follow these steps: ### Step 1: Find the resultant vector \( \mathbf{R} \) The resultant vector \( \mathbf{R} \) is given by the vector sum of \( \mathbf{A} \) and \( \mathbf{B} \). \[ \mathbf{R} = \mathbf{A} + \mathbf{B} = (4\hat{i} - 3\hat{j}) + (8\hat{i} + 8\hat{j}) \] ### Step 2: Combine the components Now, we combine the \( \hat{i} \) and \( \hat{j} \) components separately. \[ \mathbf{R} = (4 + 8)\hat{i} + (-3 + 8)\hat{j} = 12\hat{i} + 5\hat{j} \] ### Step 3: Calculate the magnitude of the resultant vector \( |\mathbf{R}| \) The magnitude of the resultant vector \( |\mathbf{R}| \) is calculated using the Pythagorean theorem. \[ |\mathbf{R}| = \sqrt{(12)^2 + (5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \] ### Step 4: Find the unit vector \( \hat{u} \) The unit vector \( \hat{u} \) parallel to the resultant vector \( \mathbf{R} \) is given by: \[ \hat{u} = \frac{\mathbf{R}}{|\mathbf{R}|} \] Substituting the values we found: \[ \hat{u} = \frac{12\hat{i} + 5\hat{j}}{13} \] ### Final Result Thus, the unit vector parallel to the resultant of vectors \( \mathbf{A} \) and \( \mathbf{B} \) is: \[ \hat{u} = \frac{12}{13}\hat{i} + \frac{5}{13}\hat{j} \]

To find the unit vector parallel to the resultant of the vectors \( \mathbf{A} = 4\hat{i} - 3\hat{j} \) and \( \mathbf{B} = 8\hat{i} + 8\hat{j} \), we will follow these steps: ### Step 1: Find the resultant vector \( \mathbf{R} \) The resultant vector \( \mathbf{R} \) is given by the vector sum of \( \mathbf{A} \) and \( \mathbf{B} \). \[ \mathbf{R} = \mathbf{A} + \mathbf{B} = (4\hat{i} - 3\hat{j}) + (8\hat{i} + 8\hat{j}) \] ...
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DC PANDEY ENGLISH-VECTORS-Single Correct
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