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Let the angle between two nonzero vector...

Let the angle between two nonzero vector `vecA and vecB` is `120^@` and its resultant be `vecC`.

A

C must be equal to |A-B|

B

C must be less than |A_B|

C

C must be greater than |A-B|

D

C may be equal to |A-B|

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the two vectors \(\vec{A}\) and \(\vec{B}\) and their resultant vector \(\vec{C}\) when the angle between them is \(120^\circ\). ### Step 1: Understand the Resultant of Two Vectors The resultant vector \(\vec{C}\) of two vectors \(\vec{A}\) and \(\vec{B}\) can be calculated using the formula: \[ |\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}|\cos(\theta)} \] where \(\theta\) is the angle between the two vectors. ### Step 2: Substitute the Given Values In this case, the angle \(\theta = 120^\circ\). We know that: \[ \cos(120^\circ) = -\frac{1}{2} \] Now, substituting this into the resultant formula gives: \[ |\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}| \left(-\frac{1}{2}\right)} \] This simplifies to: \[ |\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 - |\vec{A}||\vec{B}|} \] ### Step 3: Analyze the Magnitude of \(\vec{C}\) Now, we can analyze the magnitude of \(\vec{C}\) in relation to \(|\vec{A} - \vec{B}|\). The magnitude of the difference of two vectors is given by: \[ |\vec{A} - \vec{B}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 - 2|\vec{A}||\vec{B}|\cos(\theta)} \] Substituting \(\theta = 120^\circ\) into this formula gives: \[ |\vec{A} - \vec{B}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + |\vec{A}||\vec{B}|} \] ### Step 4: Compare \(|\vec{C}|\) and \(|\vec{A} - \vec{B}|\) Now we need to compare the two magnitudes: 1. For \(|\vec{C}|\): \[ |\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 - |\vec{A}||\vec{B}|} \] 2. For \(|\vec{A} - \vec{B}|\): \[ |\vec{A} - \vec{B}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + |\vec{A}||\vec{B}|} \] ### Step 5: Conclusion Since \(|\vec{C}|\) has a negative term and \(|\vec{A} - \vec{B}|\) has a positive term, we can conclude that: \[ |\vec{C}| < |\vec{A} - \vec{B}| \] Thus, the correct answer to the options given in the question is: - **C must be less than A - B**.

To solve the problem, we need to analyze the relationship between the two vectors \(\vec{A}\) and \(\vec{B}\) and their resultant vector \(\vec{C}\) when the angle between them is \(120^\circ\). ### Step 1: Understand the Resultant of Two Vectors The resultant vector \(\vec{C}\) of two vectors \(\vec{A}\) and \(\vec{B}\) can be calculated using the formula: \[ |\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}|\cos(\theta)} \] where \(\theta\) is the angle between the two vectors. ...
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