The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is `s=12 m`.

Answer

A, C, D

Explanation

`v dv=ads`
`:. int_0^v vdv=int_0^(12m) a ds`
`:. v^2/2` = area under a-s graph from `s=0` to `s=12m`
`=2+12+6+4`
`=24 m^2//s^2`
or `v=sqrt48 m//s =4 sqrt3 m//s`