In the system shown in figure all surface are smooth.Rod is moved by external agent with acceleration `9 ms^(-2)` vertically downwards.Force exerted on the rod by the wedge will be

Options

A. `120 N`
B. `200 N`
C. `160 N`
D. `180 N`

Answer

B

Explanation

`(9)/(a) = tan 37^(@) = (3)/(4)`
`:. a = 12 m//s^(2)`
Let `N =` normal reation between rod and wedge.Then `N sin 37^(@)` will provide the necessary `ma` force to the wedge
`:. N sin 37^(@) = ma = (10) (12) = 120`
`N = (120)/(sin 37^(@)) = (120)/(0.6)`
`= 200 N`