An object of mass 5 kg falls from rest through a vertical distance of `20 m` and attains a velocity of 10 m/s. How much work is done by the resistance of the air on the object? `(g=10m//s^(2))`.
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To solve the problem of how much work is done by the resistance of air on an object falling from rest, we can use the work-energy theorem. Here’s a step-by-step solution:
### Step 1: Identify the given values
- Mass of the object, \( m = 5 \, \text{kg} \)
- Distance fallen, \( h = 20 \, \text{m} \)
- Final velocity, \( v = 10 \, \text{m/s} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
...
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