A body is displaced from prigin to (1m,1m) by force
`F=(2yhati + 3x^(2)hatj)` along two paths
(a) `x=y` (b) `y=x^(2)`
Find the work done along both paths.

Explanation

To solve the problem of calculating the work done by the force \( \mathbf{F} = (2y \hat{i} + 3x^2 \hat{j}) \) along two different paths from the origin to the point (1m, 1m), we will follow these steps:

### Step 1: Understand the Work Done Formula
The work done \( W \) by a force along a path is given by the line integral:
\[ W = \int_C \mathbf{F} \cdot d\mathbf{r} \]
where \( d\mathbf{r} \) is the differential displacement vector along the path \( C \).
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