Home
Class 11
PHYSICS
A bode mass m is projected at an angle t...

A bode mass m is projected at an angle `theta` with the horizontal with an initial velocity u, the average power of gravitational force over the whole time of flight is.

A

`mgu cos theta`

B

`1/2mgsqrt(u cos theta)`

C

`1/2mgu sin theta`

D

`zero`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the average power of the gravitational force over the whole time of flight for a body projected at an angle θ with an initial velocity u, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Forces Involved**: - When a body is projected at an angle θ, it experiences gravitational force acting downwards. The gravitational force (weight) is given by \( F_g = mg \), where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. 2. **Identify the Displacement**: - The body moves in a projectile motion, which has both horizontal and vertical components. However, the work done by the gravitational force depends on the vertical displacement. 3. **Calculate Work Done by Gravitational Force**: - The work done by a force is given by the formula: \[ W = F \cdot d \cdot \cos(\phi) \] where \( \phi \) is the angle between the force and the displacement. - In this case, the gravitational force acts vertically downwards while the displacement during the entire time of flight has a horizontal component. Thus, the angle \( \phi \) between the gravitational force and the horizontal displacement is 90 degrees. - Since \( \cos(90^\circ) = 0 \), the work done by the gravitational force is: \[ W_g = mg \cdot d \cdot \cos(90^\circ) = 0 \] 4. **Calculate Average Power**: - Average power is defined as the work done divided by the time taken: \[ P_{avg} = \frac{W}{t} \] - Since the work done \( W_g = 0 \), we substitute this into the average power formula: \[ P_{avg} = \frac{0}{t} = 0 \] 5. **Conclusion**: - Therefore, the average power of the gravitational force over the whole time of flight is \( 0 \). ### Final Answer: The average power of the gravitational force over the whole time of flight is \( 0 \). ---

To solve the problem of finding the average power of the gravitational force over the whole time of flight for a body projected at an angle θ with an initial velocity u, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Forces Involved**: - When a body is projected at an angle θ, it experiences gravitational force acting downwards. The gravitational force (weight) is given by \( F_g = mg \), where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. 2. **Identify the Displacement**: ...
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 1 subjective|27 Videos
  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 2 Objective|30 Videos
  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 1 Assertion And Reason|12 Videos
  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Integer Type Question|11 Videos
  • WORK, ENERGY AND POWER

    DC PANDEY ENGLISH|Exercise MEDICAL ENTRACES GALLERY|33 Videos
DC PANDEY ENGLISH-WORK, ENERGY & POWER-Level 1 Objective
  1. A ball is dropped at t=0 from a height on a elastic surface. Identify ...

    Text Solution

    |

  2. A block of mass 5 kg is raised from the bottom of the lake to a height...

    Text Solution

    |

  3. A bode mass m is projected at an angle theta with the horizontal with...

    Text Solution

    |

  4. A spring of force constant k is cut in two parts at its one-third ling...

    Text Solution

    |

  5. A particle moves under the action of a force F=20hati + 15hatj along a...

    Text Solution

    |

  6. A system of wedge and block as shown in figure, is released with the s...

    Text Solution

    |

  7. A forceF=(3thati + 5hatj)N acts on a body due to which its displacemen...

    Text Solution

    |

  8. An open knife of mass m is dropped from a height h on a wooden floor. ...

    Text Solution

    |

  9. Two springs have force constants k(A) such that k(B)=2k(A). The four e...

    Text Solution

    |

  10. A mass of 0.5 kg moving with a speed of 1.5 m//s on a horizontal smoot...

    Text Solution

    |

  11. A bullet moving with a speed of 100 ms^(-1) can just penetrate into tw...

    Text Solution

    |

  12. A body of mass 100 g is attached to a hanging spring force constant is...

    Text Solution

    |

  13. An ideal massless spring S can compressed 1.0 m in equilibrium by a fo...

    Text Solution

    |

  14. A body of mass m is released from a height h on a smooth inclined plan...

    Text Solution

    |

  15. A block of mass m is directly pulled up slowly on a smooth inclined pl...

    Text Solution

    |

  16. A spring of natural length l is compressed vertically downward agains...

    Text Solution

    |

  17. The relationship between the force F and position x of body is as show...

    Text Solution

    |

  18. Under the action of a force, a 2 kg body moves such that its position ...

    Text Solution

    |

  19. The kinetic energy of a projectile at its highest position is K. If th...

    Text Solution

    |

  20. Power applied to a particle varices with time as P =(3t^(2)-2t + 1) wa...

    Text Solution

    |