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A bode mass m is projected at an angle t...

A bode mass m is projected at an angle `theta` with the horizontal with an initial velocity u, the average power of gravitational force over the whole time of flight is.

A

`mgu cos theta`

B

`1/2mgsqrt(u cos theta)`

C

`1/2mgu sin theta`

D

`zero`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the average power of the gravitational force over the whole time of flight for a body projected at an angle θ with an initial velocity u, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Forces Involved**: - When a body is projected at an angle θ, it experiences gravitational force acting downwards. The gravitational force (weight) is given by \( F_g = mg \), where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. 2. **Identify the Displacement**: - The body moves in a projectile motion, which has both horizontal and vertical components. However, the work done by the gravitational force depends on the vertical displacement. 3. **Calculate Work Done by Gravitational Force**: - The work done by a force is given by the formula: \[ W = F \cdot d \cdot \cos(\phi) \] where \( \phi \) is the angle between the force and the displacement. - In this case, the gravitational force acts vertically downwards while the displacement during the entire time of flight has a horizontal component. Thus, the angle \( \phi \) between the gravitational force and the horizontal displacement is 90 degrees. - Since \( \cos(90^\circ) = 0 \), the work done by the gravitational force is: \[ W_g = mg \cdot d \cdot \cos(90^\circ) = 0 \] 4. **Calculate Average Power**: - Average power is defined as the work done divided by the time taken: \[ P_{avg} = \frac{W}{t} \] - Since the work done \( W_g = 0 \), we substitute this into the average power formula: \[ P_{avg} = \frac{0}{t} = 0 \] 5. **Conclusion**: - Therefore, the average power of the gravitational force over the whole time of flight is \( 0 \). ### Final Answer: The average power of the gravitational force over the whole time of flight is \( 0 \). ---

To solve the problem of finding the average power of the gravitational force over the whole time of flight for a body projected at an angle θ with an initial velocity u, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Forces Involved**: - When a body is projected at an angle θ, it experiences gravitational force acting downwards. The gravitational force (weight) is given by \( F_g = mg \), where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. 2. **Identify the Displacement**: ...
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