Find the position of centre of mass of the section shown in figure

Answer

A

Explanation

`x_(CM)=(A_1x_1-A_2x_2)/(A_1-A_2)`
`=((4a^2)(a)-(a^2)(3a//2))/(4a^2-a^2)=(5a)/(6)`
`y_(CM)=(A_1y_1-A_2y_2)/(A_1-A_2)`
`=((4a^2)(a)-(a^2)(3a//2))/(4a^2-a^2)`
`=(5a)/(6)`