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Three balls A, B and C are placed on a smooth horizontal surface. Given that `m_A=m_C=4m_B`. Ball B collides with ball C with an initial velocity v as shown in figure. Find the total number of collisions between the balls. All collisions are elastic.

Text Solution

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After first collision with `B+C`

`v_B^()'=((m-4m)/(m+4m))v=-3/5v`
`v_C^()'=((2xxm)/(m+4m))v=2/5v`
After second collision with `B+A`

Now since `9/25vlt2/5v` or `v_C`
So, B will not collide with C further,
Hence total collisions are only 2.
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