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In an inelastic collision (a) momentum o...

In an inelastic collision (a) momentum of the system is always conserved (b) velocity of separation is less than the velocity of approach. (c) the coefficient of restitution can be zero. (d) All of the above

A

(a) momentum of the system is always conserved

B

(b) velocity of separation is less than the velocity of approach.

C

(c) the coefficient of restitution can be zero

D

(d) All of the above

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The correct Answer is:
To solve the question regarding inelastic collisions and determine which statements are correct, let's analyze each statement step by step. ### Step 1: Understanding Inelastic Collisions Inelastic collisions are defined as collisions where kinetic energy is not conserved, but momentum is conserved. This means that some kinetic energy is transformed into other forms of energy (like heat or sound) during the collision. ### Step 2: Analyzing Statement (a) **Statement (a):** "Momentum of the system is always conserved." - In an inelastic collision, the total momentum before the collision equals the total momentum after the collision. Therefore, this statement is **true**. ### Step 3: Analyzing Statement (b) **Statement (b):** "Velocity of separation is less than the velocity of approach." - The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation to the relative velocity of approach. For inelastic collisions, this coefficient can be less than 1, and in some cases, it can be 0. Hence, the velocity of separation is indeed less than the velocity of approach. This statement is also **true**. ### Step 4: Analyzing Statement (c) **Statement (c):** "The coefficient of restitution can be zero." - The coefficient of restitution can be zero in perfectly inelastic collisions, where the two colliding bodies stick together after the collision. Therefore, this statement is also **true**. ### Step 5: Conclusion Since all three statements (a), (b), and (c) are true, the correct answer is: **(d) All of the above.** ### Final Answer: The correct option is **(d) All of the above.** ---
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STATEMENT-1 : In an elastic collision between two bodies, the relative velocity of separation equals relative velocity of approach. and STATEMENT-2 : In a elastic collision , the coefficient of restitution is 1 .

Assertion: For inelastic collision, 0leelt1 . Reason: Hence, the magnitude of relative velocity of separation after collision is less than relative velocity of approach before collision.

Comprehension # 2 When two bodies collide normally they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :- e = |"Relative velocity of separation"|/|"Relative velocity of approach"| = 1 , for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. For what value of J (in Ns ) the 2 kg block will change its direction of velocity?

Comprehension # 2 When two bodies collide normally they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :- e = |"Relative velocity of separation"|/|"Relative velocity of approach"| = 1 , for elastic collision. Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is ............. Ns .

A particle of mass m=1 kg collides with the end with velocity v_(0)=6 ms^(-1) of a spinning rod of mass 2m and length l=1 m at the end of the rod. If the coefficient of restitution of collision e=(2//3), find the a. velocity of the particle b. angular velocity of the rod just after the impact.

A rod AB of mass M and length 8l lies on a smooth horizontal surface. A particle, of mass m and velocity v_(0) strike's the rod perpendicular to its length, as shown in Fig. As a result of the collision, the centre of mass of the rod attains a speed of v_(0)//8 and the particle rebounds back with a speed of v_(0)//4 . Find the following: a. The ratio M//m . b. The angular velocity of the rod about O . c. The coefficient of restitution 'e' for the collision. d. The velocities of the ends 'A' and 'B' of the rod, namely, v_(A) and v_(B) respectively.

According to the principle of conservation of linear momentum, if the external force acting on the system is zero, the linear momentum of the system will remain conserved. It means if the centre of mass of a system is initially at rest, it will remain, at rest in the absence of external force, that is, the displacement of centre of mass will be zero. Two blocks of masses 'm' and '2m' are placed as shown in Fig. There is no friction anywhere. A spring of force constant k is attached to the bigger block. Mass 'm' is kept in touch with the spring but not attached to it. 'A' and 'B' are two supports attached to '2m' . Now m is moved towards left so that spring is compressed by distance 'x' and then the system is released from rest. Find the relative velocity of the blocks after 'm' leaves contact with the spring.

Anwer carefully, with reasons: a) In an elastic collision of two billiard balls, is the total kinetic energy conserved during the short time of collision of the balls (i.e. when they are in contact)? Is the total linear momentum conserved during the short time of an elastic collision of two balls? c) What are the answers to a) and b) for an inelastic collision? d) If the potenital energy of two billiard balls depends only on the separation distance between their centers, is the collision elastic or inelastic? (note we are talking here of potential energy corresponding to the force during collision, not gravitational potential energy).

A particle of mass 2kg moving with a velocity 5hatim//s collides head-on with another particle of mass 3kg moving with a velocity -2hatim//s . After the collision the first particle has speed of 1.6m//s in negative x-direction, Find (a) velocity of the centre of mass after the collision, (b) velocity of the second particle after the collision. (c) coefficient of restitution.

A particle of mass 2kg moving with a velocity 5hatim//s collides head-on with another particle of mass 3kg moving with a velocity -2hatim//s . After the collision the first particle has speed of 1.6m//s in negative x-direction, Find (a) velocity of the centre of mass after the collision, (b) velocity of the second particle after the collision. (c) coefficient of restitution.

DC PANDEY ENGLISH-CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION-Level 1 Objective
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  15. The centre of mass of a non uniform rod of length L, whose mass per un...

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