A small ball of mass 1.0 kg is attached to one end of a 1.0 m long massless string and te other end of the string is hung from a point `O`. When the resulting pendulum is making `30^(@)C` from the vertical, what is the magnitude of net torque about the point of suspension? [Take `g=10m//s^(2)`]
Text Solution
AI Generated Solution
To find the magnitude of the net torque about the point of suspension when the pendulum is at an angle of \(30^\circ\) from the vertical, we can follow these steps:
### Step-by-Step Solution:
1. **Identify the Forces Acting on the Ball:**
- The ball has a mass \(m = 1.0 \, \text{kg}\).
- The weight of the ball \(F_g = mg = 1.0 \, \text{kg} \times 10 \, \text{m/s}^2 = 10 \, \text{N}\) acts downward.
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