A force `F=(2hati+3hatj+4hatk)N` is acting at point `P(2m,-3m,6m)` find torque of this force about a point `O` whose position vector is
`(2hati-5hatj+3hatk)` m.

Explanation

To find the torque of the force \( \mathbf{F} = (2\hat{i} + 3\hat{j} + 4\hat{k}) \, \text{N} \) acting at point \( P(2 \, \text{m}, -3 \, \text{m}, 6 \, \text{m}) \) about point \( O(2 \, \text{m}, -5 \, \text{m}, 3 \, \text{m}) \), we can follow these steps:

### Step 1: Determine the position vector \( \mathbf{R} \)
The position vector \( \mathbf{R} \) from point \( O \) to point \( P \) is given by:
\[ \mathbf{R} = \mathbf{R}_P - \mathbf{R}_O \]
Where:
...