A solid disc is rolling without slipping on a horizontal ground as shown in figure. Its total kinetic energy is 100 J. what is its translational and rotational kinetic energy?

Explanation

In case of pure rooilling ratio of rational kinetic energy and tranlational kinetic energy is `(1)/(2)`
or `(K_(R))/(K_(T))=(1)/(2)impliesthereforeK_(R)=((1)/(1+2))` (total kinetic energy)
`=(1)/(3)(100J)=(100)/(3)J`
Similarly `K_(T)=((2)/(1+2))` (total kintic energy )
`=(2)/(3)(100J)=(200)/(3)J`