A tangential force `F` acts at the top of a thin spherical shell of mass `m` and radius `R`. Find the acceleration of the shell if it rolls without slipping.
Text Solution
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Let `f` be the force of friction between the shell and the horizontal surface. Force translational motion `F=f=ma` ..(i) For translational motion, `FR-fR=Ialpha=I(a)/(R)` `[because a=Ralpha` for pure rolling] Adding eqs. (i) and (ii) we get `2F=(m+(I)/(R^(2)))a` `=(m+(2)/(3)m)a=(5)/(3)ma` or `F=(5)/(6)ma` `[becauseI_("shell")=(2)/(3)mR^(2)]` `impliesa=(6F)/(5m)`
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DC PANDEY ENGLISH-ROTATIONAL MECHANICS-Subjective Questions
Let `f` be the force of friction between the shell and the horizontal surface. 
