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A particle of mass 20 g experiences a g...

A particle of mass `20 g` experiences a gravitational force of `4.0 N` along positive x - direction. Find the gravitational field at that point.

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To solve the problem, we need to find the gravitational field at a point where a particle of mass 20 g experiences a gravitational force of 4.0 N. We can use the relationship between gravitational field (E), gravitational force (F), and mass (m). ### Step-by-Step Solution: 1. **Convert the mass from grams to kilograms**: - The mass of the particle is given as 20 g. - To convert grams to kilograms, we use the conversion factor \(1 \text{ g} = 0.001 \text{ kg}\). - Therefore, \( m = 20 \text{ g} = 20 \times 10^{-3} \text{ kg} = 0.020 \text{ kg} \). 2. **Use the formula for gravitational field**: - The gravitational field (E) is defined as the force (F) experienced by a mass (m) per unit mass. - The formula is given by: \[ E = \frac{F}{m} \] - Here, \( F = 4.0 \text{ N} \) and \( m = 0.020 \text{ kg} \). 3. **Substitute the values into the formula**: - Now, substituting the values into the formula: \[ E = \frac{4.0 \text{ N}}{0.020 \text{ kg}} \] 4. **Calculate the gravitational field**: - Performing the division: \[ E = \frac{4.0}{0.020} = 200 \text{ N/kg} \] 5. **Determine the direction of the gravitational field**: - The problem states that the gravitational force acts along the positive x-direction. - Therefore, the gravitational field vector can be represented as: \[ \vec{E} = 200 \hat{i} \text{ N/kg} \] ### Final Answer: The gravitational field at that point is \( \vec{E} = 200 \hat{i} \text{ N/kg} \). ---

To solve the problem, we need to find the gravitational field at a point where a particle of mass 20 g experiences a gravitational force of 4.0 N. We can use the relationship between gravitational field (E), gravitational force (F), and mass (m). ### Step-by-Step Solution: 1. **Convert the mass from grams to kilograms**: - The mass of the particle is given as 20 g. - To convert grams to kilograms, we use the conversion factor \(1 \text{ g} = 0.001 \text{ kg}\). - Therefore, \( m = 20 \text{ g} = 20 \times 10^{-3} \text{ kg} = 0.020 \text{ kg} \). ...
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