A projectile is fired vertically from the earth's surface with an initial speed of `10 km//s`. Neglecting air drag, how high above the surface of earth will it go?

Options

A. `2.51xx10^7m`
B. `2.51xx10^4m`
C. `3.51xx10^7m`
D. `2.51xx10^9m`

Answer

A, B, D

Explanation

`h = nu^(2)/(2g - (nu^(2)//R))`
`= (10^(4))^(2)/(2 xx 9.8 - (10^(4))^(2)/(6.4 xx 10^(6)))`
`= 2.51 xx 10^(7) m`
`= 2.51 xx 10^(4) km`