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The Gauss' theorem for gravitational fie...

The Gauss' theorem for gravitational field may be written as

A

`oint g*dS = (m)/(G)`

B

`- oint g*dS = 4 pi mG`

C

`oint g*dS = (m)/(4 piG)`

D

`- oint g*dS = (m)/( G)`

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The correct Answer is:
To rewrite Gauss' theorem for the gravitational field, we start by recalling the form of Gauss' theorem for electric fields and then adapt it to gravitational fields. ### Step-by-Step Solution: 1. **Understanding Gauss' Theorem for Electric Fields:** Gauss' theorem for electric fields states that: \[ \oint \mathbf{E} \cdot d\mathbf{s} = \frac{Q_{\text{enc}}}{\epsilon_0} \] where \( \mathbf{E} \) is the electric field, \( d\mathbf{s} \) is a differential area vector on a closed surface, \( Q_{\text{enc}} \) is the charge enclosed by the surface, and \( \epsilon_0 \) is the permittivity of free space. 2. **Comparing Electric and Gravitational Fields:** In the case of gravitational fields, we denote the gravitational field intensity as \( \mathbf{g} \) and the mass enclosed as \( M \). The gravitational field intensity due to a mass \( M \) at a distance \( r \) is given by: \[ \mathbf{g} = \frac{G M}{r^2} \] where \( G \) is the gravitational constant. 3. **Rewriting Gauss' Theorem for Gravitational Fields:** By analogy, we can write Gauss' theorem for gravitational fields as: \[ \oint \mathbf{g} \cdot d\mathbf{s} = \frac{M_{\text{enc}}}{G} \] where \( M_{\text{enc}} \) is the mass enclosed by the surface. 4. **Relating to the Electric Field Equation:** From the electric field equation, we can relate the constants: \[ \epsilon_0 = \frac{1}{4 \pi G} \] Thus, substituting this into our gravitational Gauss' theorem gives: \[ \oint \mathbf{g} \cdot d\mathbf{s} = 4 \pi G M_{\text{enc}} \] 5. **Including the Direction of Gravitational Field:** Since the gravitational field is always attractive, we include a negative sign to indicate this nature: \[ \oint \mathbf{g} \cdot d\mathbf{s} = -4 \pi G M_{\text{enc}} \] ### Final Expression: Thus, the Gauss' theorem for the gravitational field can be written as: \[ \oint \mathbf{g} \cdot d\mathbf{s} = -4 \pi G M_{\text{enc}} \]

To rewrite Gauss' theorem for the gravitational field, we start by recalling the form of Gauss' theorem for electric fields and then adapt it to gravitational fields. ### Step-by-Step Solution: 1. **Understanding Gauss' Theorem for Electric Fields:** Gauss' theorem for electric fields states that: \[ \oint \mathbf{E} \cdot d\mathbf{s} = \frac{Q_{\text{enc}}}{\epsilon_0} ...
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DC PANDEY ENGLISH-GRAVITATION-Level 1 Single Correct
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