Home
Class 11
PHYSICS
(a) Does it take more energy to get a sa...

(a) Does it take more energy to get a satellite upto `1500 km` above earth than to put in circular orbit once it is there.
(b) What about `3185 km` ?
(c ) What about `4500 km`? (Take `R_(e) = 6370 km`)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the energy required to lift a satellite to a certain height above the Earth and the energy required to put it into orbit at that height. We will do this for three different heights: 1500 km, 3185 km, and 4500 km. Given: - Radius of the Earth, \( R_e = 6370 \) km - Gravitational constant, \( G \) - Mass of the Earth, \( M \) - Mass of the satellite, \( m \) ### (a) For a height of 1500 km: 1. **Calculate the change in potential energy (\( \Delta E_1 \)) when raising the satellite to 1500 km:** \[ \Delta E_1 = -\frac{GMm}{R} + \frac{GMm}{R + H} \] Here, \( H = 1500 \) km, and \( R = 6370 \) km. \[ \Delta E_1 = -\frac{GMm}{6370} + \frac{GMm}{6370 + 1500} \] \[ \Delta E_1 = GMm \left( \frac{1}{6370 + 1500} - \frac{1}{6370} \right) \] 2. **Calculate the change in kinetic energy (\( \Delta E_2 \)) when the satellite is in orbit:** The orbital velocity \( v \) at height \( H \) is given by: \[ v = \sqrt{\frac{GM}{R + H}} \] The kinetic energy is: \[ \Delta E_2 = \frac{1}{2} mv^2 = \frac{1}{2} m \left( \frac{GM}{R + H} \right) \] \[ \Delta E_2 = \frac{GMm}{2(R + H)} \] 3. **Compare \( \Delta E_1 \) and \( \Delta E_2 \):** We need to determine whether \( \Delta E_1 \) is greater than or less than \( \Delta E_2 \). ### (b) For a height of 3185 km: 1. **Calculate \( \Delta E_1 \):** \[ \Delta E_1 = GMm \left( \frac{1}{6370 + 3185} - \frac{1}{6370} \right) \] 2. **Calculate \( \Delta E_2 \):** \[ \Delta E_2 = \frac{GMm}{2(6370 + 3185)} \] 3. **Compare \( \Delta E_1 \) and \( \Delta E_2 \):** ### (c) For a height of 4500 km: 1. **Calculate \( \Delta E_1 \):** \[ \Delta E_1 = GMm \left( \frac{1}{6370 + 4500} - \frac{1}{6370} \right) \] 2. **Calculate \( \Delta E_2 \):** \[ \Delta E_2 = \frac{GMm}{2(6370 + 4500)} \] 3. **Compare \( \Delta E_1 \) and \( \Delta E_2 \):** ### Final Comparison: For each height, after calculating \( \Delta E_1 \) and \( \Delta E_2 \), we will determine if it takes more energy to lift the satellite to that height or to put it into orbit.

To solve the question, we need to analyze the energy required to lift a satellite to a certain height above the Earth and the energy required to put it into orbit at that height. We will do this for three different heights: 1500 km, 3185 km, and 4500 km. Given: - Radius of the Earth, \( R_e = 6370 \) km - Gravitational constant, \( G \) - Mass of the Earth, \( M \) - Mass of the satellite, \( m \) ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    DC PANDEY ENGLISH|Exercise Level 2 Single Correct|22 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise Level 2 More Than One Correct|10 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise Level 1 Single Correct|27 Videos
  • GENERAL PHYSICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|2 Videos
  • KINEMATICS

    DC PANDEY ENGLISH|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

Estimate whether it takes more energy to get a satellite upto 1600 km above the earth than to put in orbit there. Earth's radius is 6400 km . Does your answer remain same for height 3200 km or for height 4800 km ?

What will be the acceleration due to gravity at a distance of 3200 km below the surface of the earth ? (Take R_(e)=6400 km)

Taking the earth to be a uniform sphere of radius 6400 km and the value of g at the surface to be 10ms^(-2) , calculate the energy needed to raise a satellite of mass 2000 kg to a height of 800 km a above the earth's surface and to set it into circular orbit at that altitude.

How much below the surface of the earth does the acceleration due to gravity becomes 70% of its value at the surface of earth ? (Take R_(e)=6400 km)

An artificial satellite is moving in a circular orbit around the earth with a speed equal to 3//8 times of th emagnitude of escape velocity from the earth. If the satellite is stopped suddely in its orbit and allowed to fall freely onto the earth, then the speed with whcih it hits the surface of the earth is (take g = 10 m//s and R_(e ) = 6400 km )

The moon takes about 27.3 days to revolve around the earth in a nearly circular orbit of radius 3.84xx10^5 km . Calculate the mass of the earth from these data.

What is the orbital velocity of an artifical satellite revolving round the earth at a height 100 km?

What is a period of revolution of the earth satellite ? Ignore the height of satellite above the surface of the earth. Given, (i) the value of gravitational acceleration, g = 10 ms^(-2) (ii) radius of the earth, R_(g) =6400 km (take, pi = 3.14 )

Consider a spacecraft in an elliptical orbit around the earth At the lowest point or perigee of its orbit it is 300km above the earth's surface at the highest point or apogee it is 3000km above the earth surface (a) What is the period of the spacecraft's orbit (b) using conservation of angular momentum find the ratio of spacecraft's speed at perigee to its speed at apogee (c) Using conservation of energy find the speed at perigee and the speed at apogee (d) it is derised to have the spacecraft escape from the earth completrly if the spacecraft's rockets are fired at perigee by how much would the speed have to be increased to achieve this? What if the rockets were fired at apogee Which point in the orbit is the most efficient to use ?

A satellite is revolving round the earth in a circular orbit with a velocity of 8km/s. at a height where acceleration due to gravity is 8m//s^(2) . How high is the satellite from the earth ? (Take R = 6000 km)

DC PANDEY ENGLISH-GRAVITATION-Level 1 Subjective
  1. A particle of mass 1 kg is kept on the surface of a uniform sphere of ...

    Text Solution

    |

  2. What is the fractional decrease in the value of free-fall acceleration...

    Text Solution

    |

  3. Two masses m(1) and m(2) at an infinite distance from each other are i...

    Text Solution

    |

  4. If a satellites is revolving close to a planet of density rho with per...

    Text Solution

    |

  5. A satellite is revolving around a planet in a circular orbit. What wil...

    Text Solution

    |

  6. If the radius of the earth contracts to half of its present value with...

    Text Solution

    |

  7. Two concentric spherical shells have masses m(1), m(2) and radit R(1),...

    Text Solution

    |

  8. A semicircular wire has a length L and mass M. A particle of mass m is...

    Text Solution

    |

  9. A rocket is accelerated to speed upsilon = 2sqrt(gR) near the earth's ...

    Text Solution

    |

  10. Two spheres one of mass M has radius R. Another sphere has mass 4M and...

    Text Solution

    |

  11. A uniform solid sphere of mass M and radius a is surrounded symmetrica...

    Text Solution

    |

  12. The density inside a solid sphere of radius a is given by rho=rho0/r, ...

    Text Solution

    |

  13. Two neutron stars are separated by a distance of 10^(10) m. They each ...

    Text Solution

    |

  14. A mass m is taken to a height R from the surface of the earth and then...

    Text Solution

    |

  15. In the figure masses 400 kg and 100 kg are fixed. (a) How much wo...

    Text Solution

    |

  16. Two identical stars of mass M orbit around their centre of mass. Each ...

    Text Solution

    |

  17. Consider two satellites A and B of equal mass, moving in the same circ...

    Text Solution

    |

  18. In a certain binary star system, each star has the same mass as our su...

    Text Solution

    |

  19. (a) Does it take more energy to get a satellite upto 1500 km above ear...

    Text Solution

    |