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Which of the following is not simple har...

Which of the following is not simple harmonic function ?

A

`y = a sin 2omegat + b cos^(2) omegat`

B

`y = a sin omega t + b cos 2 omega t`

C

`y = 1 - 2 sin^(2) omega t`

D

`y = (sqrt(a^(2) +b^(2)))sin omega t cos omega t`

Text Solution

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The correct Answer is:
To determine which of the given equations is not a simple harmonic function, we need to analyze each equation based on the standard forms of simple harmonic motion (SHM). The standard equations for SHM are: 1. \( x = a \sin(\omega t + \phi) \) 2. \( x = a \cos(\omega t + \phi) \) Now, let's evaluate each option one by one: ### Step 1: Analyze Each Equation 1. **Equation A: \( y = a \sin(2\omega t) + B \cos^2(\omega t) \)** We can rewrite \( \cos^2(\omega t) \) using the double angle identity: \[ \cos^2(\omega t) = \frac{1 + \cos(2\omega t)}{2} \] Substituting this back into the equation gives: \[ y = a \sin(2\omega t) + B \left(\frac{1 + \cos(2\omega t)}{2}\right) \] This can be expressed as: \[ y = \left(a + \frac{B}{2}\right) \sin(2\omega t) + \frac{B}{2} \] Since the frequency is the same (2ω), this can be considered a simple harmonic function. 2. **Equation B: \( y = a \sin(\omega t) + B \cos(2\omega t) \)** Here, we have two different frequencies: \( \omega \) and \( 2\omega \). Since the frequencies are different, we cannot express this equation in the standard SHM form. Therefore, this equation is **not** a simple harmonic function. 3. **Equation C: \( y = 1 - \sin^2(\omega t) \)** Using the identity \( \sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2} \), we can rewrite this as: \[ y = 1 - \left(\frac{1 - \cos(2\omega t)}{2}\right) = 1 - \frac{1}{2} + \frac{\cos(2\omega t)}{2} = \frac{1}{2} + \frac{\cos(2\omega t)}{2} \] This can be expressed as: \[ y = \frac{1}{2} + \frac{1}{2} \cos(2\omega t) \] This shows that it is a simple harmonic function with frequency \( 2\omega \). 4. **Equation D: \( y = \sqrt{a^2 + b^2} \sin(\omega t) \cos(\omega t) \)** Using the identity \( \sin(\omega t) \cos(\omega t) = \frac{1}{2} \sin(2\omega t) \), we can rewrite this as: \[ y = \frac{\sqrt{a^2 + b^2}}{2} \sin(2\omega t) \] This is also a simple harmonic function with frequency \( 2\omega \). ### Conclusion After analyzing all the equations, we find that: - **Equation A** is a simple harmonic function. - **Equation B** is **not** a simple harmonic function. - **Equation C** is a simple harmonic function. - **Equation D** is a simple harmonic function. Thus, the answer is **Equation B**. ---

To determine which of the given equations is not a simple harmonic function, we need to analyze each equation based on the standard forms of simple harmonic motion (SHM). The standard equations for SHM are: 1. \( x = a \sin(\omega t + \phi) \) 2. \( x = a \cos(\omega t + \phi) \) Now, let's evaluate each option one by one: ### Step 1: Analyze Each Equation ...
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DC PANDEY ENGLISH-SIMPLE HARMONIC MOTION-Level 1 Single Correct
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  3. Which of the following is not simple harmonic function ?

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  8. A disc of radius R is pivoted at its rim. The period for small oscilla...

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  10. If the length of a simple pendulum is equal to the radius of the earth...

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  11. The displacement - time (x - t) graph of a particle executing simple h...

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  12. In the figure shown the time period and the amplitude respectively, wh...

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  13. The equation of motion of a particle of mass 1g is (d^(2)x)/(dt^(2)) +...

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  14. The spring as shown in figure is kept in a stretched position with ext...

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  15. The mass and diameter of a planet are twice those of earth. What will ...

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  16. The resultant amplitude due to superposition of three simple harmonic ...

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  17. Two SHMs s(1) = a sin omega t and s(2) = b sin omega t are superimpose...

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  18. The amplitude of a particle executing SHM about O is 10 cm. Then

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