A particle of mass `2 kg` moves in simple harmonic motion and its potential energy `U` varies with position `x` as shown. The period of oscillation of the particle is

Options

A. `(2pi)/(5)s`
B. `2sqrt(2pi)/(5)s`
C. `sqrt(2pi)/(5)s`
D. `(4pi)/(5)s`

Answer

D

Explanation

`(1)/(2) kA^(2) = 1.0`
`(1)/(2)k (0.4)^(2) = 1.0`
or `k = 12.5` or `(25)/(2)N//m`
`T = 2pi sqrt ((m)/(k)) = 2pi sqrt ((2)/((25)/(2))) = (4pi)/(5)s`