The spring as shown in figure is kept in a stretched position with extension `x` when the system is relesed. Assuming the horizontal surface to be frictionless, the frequency of oscillation is

Options

A. `(1)/(2pi) sqrt([(k(M + m))/(Mm)])`
B. `(1)/(2pi) sqrt([(mM)/(k(M + m))])`
C. `(1)/(2pi) sqrt([(kM)/(m + M)])`
D. `(1)/(2pi) sqrt ([(km)/(M + m)])`

Answer

A

Explanation

`f = (1)/(2pi) sqrt((k)/(mu))`
Where, `mu` = reduced mass
` = (M m)/(M + m)`.