A particle moves under the force `F(x) = (x^(2) - 6x)N`, where `x` is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?

Explanation

To find the force constant for a particle moving under the force \( F(x) = (x^2 - 6x) \) N for small displacements from the origin, we can follow these steps:

### Step 1: Understand the Force Function
The force acting on the particle is given by:
\[ F(x) = x^2 - 6x \]
where \( x \) is the displacement in meters.
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