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A 1kg block is executing simple harmonic...

A `1kg` block is executing simple harmonic motion of amplitude `0.1m` on a smooth horizontal surface under the restoring force of a spring of spring constant `100 N//m`. A block of mass `3 kg` is gently placed on it at the instant it passes through the mean position. Assuming that the two blocks move together. Find the frequency and the amplitude of the motion.

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To solve the problem step by step, we will calculate the frequency and amplitude of the motion after a 3 kg block is placed on a 1 kg block executing simple harmonic motion. ### Step 1: Calculate the initial frequency of the 1 kg block The formula for the frequency \( f \) of a mass-spring system is given by: \[ f = \frac{1}{2\pi} \sqrt{\frac{k}{m}} ...
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