A particle that hangs from a spring oscillates with an angular frequency of `2 rad//s`. The spring particle system is suspended from the celling of an elevator car and hangs motionless (relative to the elevator car) as the car descends at a constant speed of `1.5 m//s`. The car then stops suddenly. (a) With what amplitude does the particle oscillate ? (b) What is the equation of motion for the particle ? (Choose upward as the position direction)

Answer

A, B

Explanation

`1.5 = omega A = 2 A rArr :. A = 0.75 m`
Further, the particle will start its journey from its mean position in downward direction
( `- ve` direction).