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At x = (A)/(4), what fraction of the mec...

At `x = (A)/(4)`, what fraction of the mechanical energy is potential ? What fraction is kinetic ? Assume potential energy to be zero at mean position.

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To solve the problem, we need to find the fractions of potential and kinetic energy when the displacement \( x \) is equal to \( \frac{A}{4} \), where \( A \) is the amplitude of the motion. We will assume that the potential energy is zero at the mean position. ### Step-by-Step Solution: 1. **Understanding Total Mechanical Energy**: The total mechanical energy \( E \) in simple harmonic motion (SHM) is given by: \[ E = \frac{1}{2} k A^2 \] where \( k \) is the spring constant and \( A \) is the amplitude. 2. **Calculating Potential Energy at \( x = \frac{A}{4} \)**: The potential energy \( U \) at a displacement \( x \) in SHM is given by: \[ U = \frac{1}{2} k x^2 \] Substituting \( x = \frac{A}{4} \): \[ U = \frac{1}{2} k \left(\frac{A}{4}\right)^2 = \frac{1}{2} k \cdot \frac{A^2}{16} = \frac{k A^2}{32} \] 3. **Expressing Potential Energy in Terms of Total Energy**: We can express the potential energy as a fraction of the total energy: \[ U = \frac{k A^2}{32} \] Since the total energy \( E = \frac{1}{2} k A^2 \), we can write: \[ \text{Fraction of potential energy} = \frac{U}{E} = \frac{\frac{k A^2}{32}}{\frac{1}{2} k A^2} = \frac{1/32}{1/2} = \frac{1}{16} \] 4. **Calculating Kinetic Energy**: The kinetic energy \( K \) can be found using the relationship: \[ K = E - U \] Substituting the values we have: \[ K = \frac{1}{2} k A^2 - \frac{k A^2}{32} \] To combine these, we need a common denominator: \[ K = \frac{16 k A^2}{32} - \frac{k A^2}{32} = \frac{15 k A^2}{32} \] 5. **Expressing Kinetic Energy in Terms of Total Energy**: Now, we can express the kinetic energy as a fraction of the total energy: \[ \text{Fraction of kinetic energy} = \frac{K}{E} = \frac{\frac{15 k A^2}{32}}{\frac{1}{2} k A^2} = \frac{15/32}{1/2} = \frac{15}{16} \] ### Final Results: - The fraction of mechanical energy that is potential at \( x = \frac{A}{4} \) is \( \frac{1}{16} \) or \( 6.25\% \). - The fraction of mechanical energy that is kinetic at \( x = \frac{A}{4} \) is \( \frac{15}{16} \) or \( 93.75\% \).

To solve the problem, we need to find the fractions of potential and kinetic energy when the displacement \( x \) is equal to \( \frac{A}{4} \), where \( A \) is the amplitude of the motion. We will assume that the potential energy is zero at the mean position. ### Step-by-Step Solution: 1. **Understanding Total Mechanical Energy**: The total mechanical energy \( E \) in simple harmonic motion (SHM) is given by: \[ E = \frac{1}{2} k A^2 ...
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