A wire havinga length `L` and cross- sectional area `A` is suspended at one of its ends from a ceiling . Density and young's modulus of material of the wire are `rho` and `Y`, respectively. Its strain energy due to its own weight is `(rho^(2)g^(2)AL^(3))/(alphaY)`. Find the vqalue of `alpha `

Explanation

To solve the problem, we need to find the value of \( \alpha \) in the expression for the strain energy of a wire suspended from one end. The given expression for strain energy is:

\[ U = \frac{\rho^2 g^2 A L^3}{\alpha Y} \]

### Step-by-Step Solution:

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