The area of cross section of the two arms of a hydraulilc press are 1 cm^2 and 10 cm^2 respectively figure. A force of 5N is applied on the water in the thinner arm. What force should be applied on the water in the thicker arm so that the water may remain in equilibrium?
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Explanation

In equilibrium the pressure at the two sufraces should be equal as they lie in the same horizontal level. If the atmospheric pressure is `p` and a force `F` is applied to maintain the equillibrium, the pressure are,
`p_(0)+(5N)/(1 cm^(2))` and `p_(0)+(F)/(10 cm^(2))`respectively.
This gives `F=50N` .