Water `(rho=10^(3)kg//m^(3))` is filled in tube AB as shown in figure. `(omega=10 rad//s)`. Tube is open at end A. Atmospheric pressure is `p_(0)=10^(5)N//m^(2)`. Find absolute pressure at end` B`.
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Answer

A, B, C

Explanation

`p_(B)=p_(A)+(rho omega^(2)x^(2))/(2)=p_(0)+(rho omega^(2)x^(2))/(2)`.