A capillary tube is dipped in a liquid. Let pressure at point `A,B` and `C` be `p_(A)p_(B)` and `p_(C)` respectively, then

1) p A = p B = p C
2)p A = p B < p C
3)p A = p C < p B
4)p A = p C > p B

Options

A. `p_(A) =p_(B) =p_(C)`
B. `p_(A) = p_(B) lt p_(C)`
C. `p_(A) = p_(C) lt p_(B)`
D. `p_(A) = p_(C) gt p_(B)`

Answer

D

Explanation

`p_(A)=p_(C)=(p_(B)+rho gh)`.