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What is the pressure drop (in mm Hg) in ...

What is the pressure drop (in mm Hg) in the blood as it passes through a capillary `1mm` long and `2mu m` in radius if the speed of the blood through the centre of the capillary is `0.66mm/s`? (The viscosity of whole blood is `4xx10^(-3) PI)`

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To solve the problem of finding the pressure drop in the blood as it passes through a capillary, we can use the formula derived from Poiseuille's law for viscous flow in a cylindrical pipe. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the given values - Length of the capillary (L) = 1 mm = \(1 \times 10^{-3}\) m - Radius of the capillary (R) = 2 µm = \(2 \times 10^{-6}\) m - Speed of blood (V_max) = 0.66 mm/s = \(0.66 \times 10^{-3}\) m/s - Viscosity of blood (η) = \(4 \times 10^{-3} \, \text{Pa.s}\) ### Step 2: Use the formula for pressure drop The pressure drop (ΔP) across a length of capillary can be calculated using the formula: \[ \Delta P = \frac{8 \eta L V_{max}}{R^2} \] This formula is derived from Poiseuille's law for laminar flow in a cylindrical tube. ### Step 3: Substitute the values into the formula Substituting the known values into the formula: \[ \Delta P = \frac{8 \times (4 \times 10^{-3}) \times (1 \times 10^{-3}) \times (0.66 \times 10^{-3})}{(2 \times 10^{-6})^2} \] ### Step 4: Calculate the denominator Calculating the denominator: \[ (2 \times 10^{-6})^2 = 4 \times 10^{-12} \] ### Step 5: Calculate the numerator Calculating the numerator: \[ 8 \times (4 \times 10^{-3}) \times (1 \times 10^{-3}) \times (0.66 \times 10^{-3}) = 8 \times 4 \times 0.66 \times 10^{-9} = 21.12 \times 10^{-9} \] ### Step 6: Calculate the pressure drop Now substituting the values into the equation: \[ \Delta P = \frac{21.12 \times 10^{-9}}{4 \times 10^{-12}} = 5.28 \times 10^{3} \, \text{Pa} \] ### Step 7: Convert pressure drop to mm Hg To convert the pressure from Pascals to mm Hg, we use the conversion factor: \[ 1 \, \text{mm Hg} = 133.322 \, \text{Pa} \] Thus, \[ \Delta P \text{ (in mm Hg)} = \frac{5.28 \times 10^{3}}{133.322} \approx 39.6 \, \text{mm Hg} \] ### Step 8: Final Answer The pressure drop in the blood as it passes through the capillary is approximately **39.6 mm Hg**. ---

To solve the problem of finding the pressure drop in the blood as it passes through a capillary, we can use the formula derived from Poiseuille's law for viscous flow in a cylindrical pipe. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the given values - Length of the capillary (L) = 1 mm = \(1 \times 10^{-3}\) m - Radius of the capillary (R) = 2 µm = \(2 \times 10^{-6}\) m - Speed of blood (V_max) = 0.66 mm/s = \(0.66 \times 10^{-3}\) m/s - Viscosity of blood (η) = \(4 \times 10^{-3} \, \text{Pa.s}\) ...
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