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One end of a horizontal rope is attached...

One end of a horizontal rope is attached to a prong of an electrically driven fork that vibrates at `120 Hz`. The other end passes over a pulley and supports a `1.50 kg` mass. The linear mass density of the rope is `0.0550 kg//m`.
(a) What is the speed of a transverse wave on the rope?
(b) Whatis the wavelength?
How would your answer to parts (a) and (b) change if the mass were increased to `3.00 kg`?

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The correct Answer is:
To solve the problem step by step, we will break it down into parts (a) and (b) as outlined in the question. ### Part (a): Finding the Speed of the Transverse Wave on the Rope 1. **Identify the Tension in the Rope**: The tension (T) in the rope is equal to the weight of the mass hanging from it. This can be calculated using the formula: \[ T = m \cdot g \] where: - \( m = 1.50 \, \text{kg} \) (mass) - \( g = 9.81 \, \text{m/s}^2 \) (acceleration due to gravity) Substituting the values: \[ T = 1.50 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 = 14.715 \, \text{N} \] 2. **Calculate the Speed of the Wave**: The speed (v) of the transverse wave on the rope can be calculated using the formula: \[ v = \sqrt{\frac{T}{\mu}} \] where: - \( \mu = 0.0550 \, \text{kg/m} \) (linear mass density) Substituting the values: \[ v = \sqrt{\frac{14.715 \, \text{N}}{0.0550 \, \text{kg/m}}} \] \[ v = \sqrt{267.545} \approx 16.35 \, \text{m/s} \] ### Part (b): Finding the Wavelength 1. **Use the Wave Speed and Frequency**: The wavelength (\(\lambda\)) can be calculated using the formula: \[ \lambda = \frac{v}{f} \] where: - \( f = 120 \, \text{Hz} \) (frequency) Substituting the values: \[ \lambda = \frac{16.35 \, \text{m/s}}{120 \, \text{Hz}} \approx 0.13625 \, \text{m} \] ### Changes When the Mass is Increased to 3.00 kg 1. **Calculate New Tension**: If the mass is increased to \( m = 3.00 \, \text{kg} \): \[ T = 3.00 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 = 29.43 \, \text{N} \] 2. **Calculate New Speed**: The new speed (\(v_2\)) can be calculated as: \[ v_2 = \sqrt{\frac{T_2}{\mu}} = \sqrt{\frac{29.43 \, \text{N}}{0.0550 \, \text{kg/m}}} \] \[ v_2 = \sqrt{535.636} \approx 23.2 \, \text{m/s} \] 3. **Calculate New Wavelength**: The new wavelength (\(\lambda_2\)) can be calculated as: \[ \lambda_2 = \frac{v_2}{f} = \frac{23.2 \, \text{m/s}}{120 \, \text{Hz}} \approx 0.1933 \, \text{m} \] ### Summary of Results - **Part (a)**: Speed of the wave with 1.5 kg mass: \( \approx 16.35 \, \text{m/s} \) - **Part (b)**: Wavelength with 1.5 kg mass: \( \approx 0.136 \, \text{m} \) - **With 3.0 kg mass**: Speed: \( \approx 23.2 \, \text{m/s} \), Wavelength: \( \approx 0.1933 \, \text{m} \)

To solve the problem step by step, we will break it down into parts (a) and (b) as outlined in the question. ### Part (a): Finding the Speed of the Transverse Wave on the Rope 1. **Identify the Tension in the Rope**: The tension (T) in the rope is equal to the weight of the mass hanging from it. This can be calculated using the formula: \[ T = m \cdot g ...
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