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Two identical straight wires are stretch...

Two identical straight wires are stretched so as to products `6 beats// s` when vibrating simultaneously. On changing the tension slightly in one of them, the beat frequency remains unchanged. Denoting by , `T_(1)` the higher and `T_(2)` the lower, initial tensions in the strings, then it could be said that that while making the above changes in tension

A

(a) `T_(2)` was decreased

B

(b) `T_(1)` was increased

C

(c) `T_(1)` was decreased

D

(d) `T_(1)`was decreased or `T_(2)` was increased

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the relationship between the tension in the wires and their frequencies, as well as the conditions under which the beat frequency remains unchanged. ### Step-by-step Solution: 1. **Understanding the Frequencies**: The frequency of a vibrating wire is given by the formula: \[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} ...
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