One end of the rod of length l, thermal conductivity K and area of cross-section A is maintained at a constant temperature of `100^@C`. At the other end large quantity of ice is kept at `0^@C` . Due to temperature difference, heat flows from left end to right end of the rod. Due to this heat ice will start melting. Neglecting the radiation losses find the expression of rate of melting of ice.
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Answer

A, D

Explanation

Putting,
`((dQ)/dt)_("conduction")=((dQ)/(dt))_("calorimetry")`
`:. (TD)/R = L* (dm)/(dt)`
`rArr (dm)/(dt) = (TD)/(RL)`
So, this is the desired expression of `(dm)/(dt)`.
In the above expression,
`TD = 100^@C, R = l/(KA)`
and L = latent heat of fusion.