The emf of a storage battery is `90 V` before charging and `100 V` after charging. When charging began the current was `10 A`. What is the current at the end of charging if the internal resistance of the storge battery during the whole process of charging may be taken as constant and equal to `2Omega`?

Explanation

To solve the problem step by step, we will follow the principles of electromotive force (emf), internal resistance, and Ohm's law.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Initial emf of the battery before charging, \( E_1 = 90 \, V \)
- Final emf of the battery after charging, \( E_2 = 100 \, V \)
- Initial current when charging began, \( I_1 = 10 \, A \)
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