What inductance would be needed to store `1.0 kWh` of energy in a coil carrying a `200 A` current. `(1kWh=3.6xx10^6J)`

Explanation

To find the inductance needed to store \(1.0 \, \text{kWh}\) of energy in a coil carrying a current of \(200 \, \text{A}\), we can follow these steps:

### Step 1: Convert energy from kWh to Joules
Given that \(1 \, \text{kWh} = 3.6 \times 10^6 \, \text{J}\), we can directly use this value for our calculations.

\[ U = 1 \, \text{kWh} = 3.6 \times 10^6 \, \text{J} \]
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