Home
Class 12
PHYSICS
A long thin solenoid has 900"tuns"//"met...

A long thin solenoid has `900"tuns"//"metre"` and radius `2.50cm`,. The current in the solenoid is increasing at a uniform rate of `60A//s`. What is the magnitude of the induced electric field at a point?
a. `0.5cm` from the axis of the solenoid.
b. `1.0cm` from the axis of the solenoid.

Text Solution

AI Generated Solution

To solve the problem, we need to find the induced electric field at two different points from the axis of a solenoid with given parameters. Let's break down the solution step by step. ### Given Data: - Number of turns per meter (n) = 900 turns/m - Radius of the solenoid (R) = 2.50 cm = 0.025 m - Rate of change of current (di/dt) = 60 A/s - Permeability of free space (μ₀) = 4π × 10^(-7) T·m/A ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Check point|60 Videos

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Taking it together|119 Videos

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|20 Videos

  • CURRENT ELECTRICITY

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|97 Videos

  • ELECTROMAGNETIC WAVES

    DC PANDEY ENGLISH|Exercise Sec C|22 Videos

Similar Questions

Explore conceptually related problems

A 0.8 m long solenoid has 800 turns and a field density of 2.52xx10^(-3) T at its certre .Find the current in the solenoid

A solenoid of length 8cm has 500 turns /m in it. If radius of coil is 3cm and if it is carrying a current of 2A, find the magnetic induction at a point 4cm from the end on the axis of the solenoid

A solenoid of length 0*5m has a radius of 1cm and is made up of 500 turns. It carries a current of 5A . What is the magnitude of the magnetic field inside the solenoid?

A long solenoid with radius 2cm carries a current of 2A . The solenoid is 70cm long and is composed of 300 turns of wire. Assuming ideal solenoid model, calculate the flux linked with a circular surface if (a) it has a radius of 1cm and is perpendicular to the axis of the solenoid: (i) inside, (ii) outside. (b)it has a radius of 3cm and is perpendicular to the axis of the solenoid with its center lying on the axis of the solenoid. ( c ) it has a radius greater than 2cm and axis of the solenoid subtend an angle of 60^(@) with the normal to the area (the center of the circular surface being on the axis of the solenoid). (d) the plane of the circular area is parallel to the axis of the solenoid.

A solenoid consists of 100 turns of wire and has a length of 10 cm. The magnetic field inside the solenoid when it carries a current of 0.5 A will be :

A solenoid of radius 2.50cm has 400turns and a length of 20.0cm. The current in the coil is changing with time such that an emf of 75X10^(-6) is produced. The rate of change of current in the solenoid is

The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A flows through it is

If the current in the toroidal solenoid increases uniformly from zero to 6.0 A in 3.0 mus Self-inductance of the toroidal solenoid is 40mu H The magnitude of self-induced emf is

A long solenoid having n = 200 turns per metre has a circular cross-section of radius a_(1) = 1 cm . A circular conducting loop of radius a_(2) = 4 cm and resistance R = 5 (Omega) encircles the solenoid such that the centre of circular loop coincides with the midpoint of the axial line of the solenoid and they have the same axis as shown in Fig. A current 't' in the solenoid results in magnetic field along its axis with magnitude B = (mu)ni at points well inside the solenoid on its axis. We can neglect the insignificant field outside the solenoid. This results in a magnetic flux (phi)_(B) through the circular loop. If the current in the winding of solenoid is changed, it will also change the magnetic field B = (mu)_(0)ni and hence also the magnetic flux through the circular loop. Obvisouly, it will result in an induced emf or induced electric field in the circular loop and an induced current will appear in the loop. Let current in the winding of solenoid be reduced at a rate of 75 A //sec . Magentic flux through the loop due to external magnetic field will be I is the current in the loop a_(1) is the radius of solendoid and a_(1)=1cm (given) a_(2) is the radius of circular loop and a_(2)=4cm (given) i is hte current in the solenoid

A long solenoid having n = 200 turns per metre has a circular cross-section of radius a_(1) = 1 cm . A circular conducting loop of radius a_(2) = 4 cm and resistance R = 5 (Omega) encircles the solenoid such that the centre of circular loop coincides with the midpoint of the axial line of the solenoid and they have the same axis as shown in Fig. A current 't' in the solenoid results in magnetic field along its axis with magnitude B = (mu)ni at points well inside the solenoid on its axis. We can neglect the insignificant field outside the solenoid. This results in a magnetic flux (phi)_(B) through the circular loop. If the current in the winding of solenoid is changed, it will also change the magnetic field B = (mu)_(0)ni and hence also the magnetic flux through the circular loop. Obvisouly, it will result in an induced emf or induced electric field in the circular loop and an induced current will appear in the loop. Let current in the winding of solenoid be reduced at a rate of 75 A //sec . When the current in the solenoid becomes zero so that external magnetic field for the loop stops changing, current in the loop will follow a differenctial equation given by [You may use an approximation that field at all points in the area of loop is the same as at the centre

DC PANDEY ENGLISH-ELECTROMAGNETIC INDUCTION-Example
  1. A capacitor of capacitance 25muF is charged to 300V. It is then connec...

    Text Solution

    |

  2. The magnetic field at all points within the cyllindrical region whose ...

    Text Solution

    |

  3. A long thin solenoid has 900"tuns"//"metre" and radius 2.50cm,. The cu...

    Text Solution

    |

  4. A uniform magnetic field exists in the space bar B = B(1) hat i+B(2) h...

    Text Solution

    |

  5. A long solenoid of radius 4 cm, length 400 cmcarries a current of 3 A....

    Text Solution

    |

  6. Figure shows a long straight wire carrying current I and a square cond...

    Text Solution

    |

  7. A coil with an average diameter of 0.02 m is placed perpendicular to a...

    Text Solution

    |

  8. A coil consists of 200 turns of wire having a total reistance of 2.0Om...

    Text Solution

    |

  9. The magnetic flux passing through a metal ring varies with time t as:...

    Text Solution

    |

  10. A square loop of side 10 cm and resistance 0.5 Omega is placed vertica...

    Text Solution

    |

  11. A wire of length l in the form of a square loop lies in a plane normal...

    Text Solution

    |

  12. Suppose a coil of area 5m^(2), resistance 10Omega and number of turns ...

    Text Solution

    |

  13. Through a long solenoid of diameter 4.1 cm, having 100 turns per cm, a...

    Text Solution

    |

  14. A square loop of edge b having M turns is rotated with a uniform angul...

    Text Solution

    |

  15. A square loop ACDE of area 20 cm^2 resistance 5Omega is rotate in as...

    Text Solution

    |

  16. The two conducting rails are placed perpendicular to each other, such ...

    Text Solution

    |

  17. A bar magnet is freel falling along the axis of a circular loop as sho...

    Text Solution

    |

  18. A bar magnet is brought near a solenoid as shown in figure. Will the s...

    Text Solution

    |

  19. In the given figure currnet from A to B in the straight wire is decrea...

    Text Solution

    |

  20. A current carrying straight wire passing inside a triangular loop as s...

    Text Solution

    |