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In an L-C circuit, L=3.3H and C=840pF. A...

In an `L-C` circuit, `L=3.3H` and `C=840pF`. At `t=0` charge on the capacitor is `105muC` and maximum. Compute the following quantities at `t=2.0ms`.
a. The energy stored in the capacitor.
b. The total energy in the circuit,
c. The energy stored in the inductor.

Text Solution

AI Generated Solution

To solve the problem step by step, we will compute the required quantities for the given `L-C` circuit. ### Given Data: - Inductance, \( L = 3.3 \, \text{H} \) - Capacitance, \( C = 840 \, \text{pF} = 840 \times 10^{-12} \, \text{F} \) - Maximum charge on the capacitor at \( t = 0 \), \( Q_0 = 105 \, \mu\text{C} = 105 \times 10^{-6} \, \text{C} \) - Time, \( t = 2.0 \, \text{ms} = 2.0 \times 10^{-3} \, \text{s} \) ...
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